Thursday, July 18, 2019

Investigating the concentration of the solutions inside the vacuole of a potato cell. :: essays research papers

Osmosis Investigation We are trying to find out what the concentration of the solutions is inside the vacuole of a potato cell. We will investigate how the mass of the potato chips change in different sucrose solution concentrations. We will use osmosis to do this. I will be measuring and controlling many different variables, these include; - The dependent Variable – Weight of potato chip Independent Variable – Concentration of sucrose Control Variables consist of; - 1.  Ã‚  Ã‚  Ã‚  Ã‚  Temperature 2.  Ã‚  Ã‚  Ã‚  Ã‚  Surface area of potato 3.  Ã‚  Ã‚  Ã‚  Ã‚  Volume of sucrose solution 4.  Ã‚  Ã‚  Ã‚  Ã‚  Same time for each potato chip submerged in solution 5.  Ã‚  Ã‚  Ã‚  Ã‚  Potato chips all from same potato The effects on the dependent variables all differ; here is how the main variables in my experiment work out. Variable  Ã‚  Ã‚  Ã‚  Ã‚   Effect on Dependent Variable Surface area of potato chip  Ã‚  Ã‚  Ã‚  Ã‚  The greater the surface area the more water it will be able to absorb Same chip from the same potato  Ã‚  Ã‚  Ã‚  Ã‚  The genetic make-up will be the same and therefore the partly permemble membrane will be similar Time left in the solution  Ã‚  Ã‚  Ã‚  Ã‚  The longer spent in solution the more that is absorbed Coating on the potato chips  Ã‚  Ã‚  Ã‚  Ã‚  If not rinsed off and dried after a certain period of time the chips will form a coat of sugar thus decreasing surface area Quantitative prediction I predict that the effect of changing the sucrose concentration will be that as the concentration of the sucrose solution increases, first of all the mass of the chip will increase, and then the change in mass will gradually decrease until mass is lost and this mass loss will gradually increase in amount. Because when the sucrose concentration is low, the concentration of water outside the cells of the potato chips will be greater than that inside, and therefore water will osmosis into the cells of the chip which will gain mass. As the concentration of sucrose increases the concentration of water outside the call will eventually become less than inside the cells of the chip and mass will be lost.   Ã‚  Ã‚  Ã‚  Ã‚  Dependent   Ã‚  Ã‚  Ã‚  Ã‚  Variable   Ã‚  Ã‚  Ã‚  Ã‚   Inside the cells Outside the cells Dilute solution  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚   Concentrated solution   Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚  Ã‚     Ã‚  Ã‚  Ã‚  Ã‚   Higher water concentration Low water concentration Key: = Sucrose particle = water molecule = osmosis = partially permeable membrane In the higher sucrose concentration solution, the net movement of water (osmosis) is to the outside of the cell, and the chip will lose mass, the cells will become plasmolysed. The chip in a low concentration of sucrose solution, is the opposite of the diagram above, in that the water osmoses into the cells of the chip, mass it gained, through osmosis of water into the plant cells, the cells will become turgid.

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